You can equate magnetic force to centripetal force
Fm = qvBsin(theta)
Fc = mv^2/r
We can for this sake assume the magnetic field is perpendicular to the motion of the particle so that trigonometric function goes away...
qvB = mv^2 / r
qBr / v = m
Friday, January 20, 2012
Different charged particles travel in circles within a magnetic field. What can you conclude about the particl?
Different charged particles travel in circles within a magnetic field. What can you conclude about the particles from the radius of their circular paths? (You may assume they all have the velocity.)Different charged particles travel in circles within a magnetic field. What can you conclude about the particl?The radii of their paths is directly related to their mass.
You can equate magnetic force to centripetal force
Fm = qvBsin(theta)
Fc = mv^2/r
We can for this sake assume the magnetic field is perpendicular to the motion of the particle so that trigonometric function goes away...
qvB = mv^2 / r
qBr / v = mpublishing companies
You can equate magnetic force to centripetal force
Fm = qvBsin(theta)
Fc = mv^2/r
We can for this sake assume the magnetic field is perpendicular to the motion of the particle so that trigonometric function goes away...
qvB = mv^2 / r
qBr / v = m
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